"Wordsworth" meaning in All languages combined

{
  "etymology_text": "Variant of Wadsworth.",
  "forms": [
    {
      "form": "Wordsworths",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "~",
        "2": "s"
      },
      "expansion": "Wordsworth (countable and uncountable, plural Wordsworths)",
      "name": "en-proper noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "English surnames",
          "parents": [],
          "source": "w"
        },
        {
          "_dis": "73 27",
          "kind": "other",
          "name": "English entries with incorrect language header",
          "parents": [
            "Entries with incorrect language header",
            "Entry maintenance"
          ],
          "source": "w+disamb"
        },
        {
          "_dis": "71 29",
          "kind": "other",
          "name": "Pages with 1 entry",
          "parents": [],
          "source": "w+disamb"
        },
        {
          "_dis": "73 27",
          "kind": "other",
          "name": "Pages with entries",
          "parents": [],
          "source": "w+disamb"
        },
        {
          "_dis": "80 20",
          "kind": "topical",
          "langcode": "en",
          "name": "Individuals",
          "orig": "en:Individuals",
          "parents": [
            "People",
            "Human",
            "All topics",
            "Fundamental"
          ],
          "source": "w+disamb"
        }
      ],
      "glosses": [
        "A habitational surname from Old English."
      ],
      "id": "en-Wordsworth-en-name-zLJicHqr",
      "links": [
        [
          "habitational",
          "habitational"
        ],
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    },
    {
      "glosses": [
        "William Wordsworth (1770 – 1850), a major English romantic poet."
      ],
      "id": "en-Wordsworth-en-name-eaKDA~JJ",
      "links": [
        [
          "English",
          "English"
        ],
        [
          "romantic",
          "romantic"
        ],
        [
          "poet",
          "poet"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    }
  ],
  "wikipedia": [
    "Wordsworth (disambiguation)"
  ],
  "word": "Wordsworth"
}

{
  "categories": [
    "English countable nouns",
    "English entries with incorrect language header",
    "English lemmas",
    "English proper nouns",
    "English uncountable nouns",
    "Pages with 1 entry",
    "Pages with entries",
    "en:Individuals"
  ],
  "etymology_text": "Variant of Wadsworth.",
  "forms": [
    {
      "form": "Wordsworths",
      "tags": [
        "plural"
      ]
    }
  ],
  "head_templates": [
    {
      "args": {
        "1": "~",
        "2": "s"
      },
      "expansion": "Wordsworth (countable and uncountable, plural Wordsworths)",
      "name": "en-proper noun"
    }
  ],
  "lang": "English",
  "lang_code": "en",
  "pos": "name",
  "senses": [
    {
      "categories": [
        "English surnames",
        "English surnames from Old English"
      ],
      "glosses": [
        "A habitational surname from Old English."
      ],
      "links": [
        [
          "habitational",
          "habitational"
        ],
        [
          "surname",
          "surname"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    },
    {
      "glosses": [
        "William Wordsworth (1770 – 1850), a major English romantic poet."
      ],
      "links": [
        [
          "English",
          "English"
        ],
        [
          "romantic",
          "romantic"
        ],
        [
          "poet",
          "poet"
        ]
      ],
      "tags": [
        "countable",
        "uncountable"
      ]
    }
  ],
  "wikipedia": [
    "Wordsworth (disambiguation)"
  ],
  "word": "Wordsworth"
}